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https://marianacustodio.com/are-art-prints-worth-anything/
Aug 20, 2020 · A trial proof is an impression that was made as a test; the artist creates this to test what needs or doesn’t need to be altered. The artist then proceeds to change the matrix accordingly. There are no annotations in trial proof.
https://wmuprintmaking.files.wordpress.com/2013/01/1_vocab-intro.pdf
Jan 01, 2013 · B.A.T - Artist’s Proof- Proof- Registration- Slip sheet- Solvent- Water-based- Non-Toxic- 2 LITHOGRAPHIC TERMS Lithography- Levigator- Limestone- Squeegee- Aluminum Plate- Carborundum Grit- Hydrophilic- Resist- Oleophilic- Litho Pencil- Talc- Litho Crayon- ...
http://danielkellystudio.com/works/rolling-in-1982/
Woodblock on Arches 90 lb. hot press watercolor paper. Edition of 100, with 10 artist’s proofs, 5 trial proofs, and 1 B.A.T. Artist’s proof dedicated to Tomikichiro Tokuriki.Printed by Toshiharu Nakagawa in Kyoto. Size: 10 x 28 in. Note: Edition also includes 2 additional proofs signed as “Trial Proof” and 1 signed as “Test Proof.” ...
https://www.estatesale.com/sales/view/11125.html
This rare B.A.T. artist's proof has been hand-signed by Yoko Ono Lennon and published exclusively by Bag One Arts, Inc. in 1996. Archivally matted and framed. Sale price - $4000 B8 ) John Lennon (artist) - Limited edition 16" x 20" lithograph with embossing created from Lennon's handwritten lyrics to the song "Imagine" #19/1000
https://quizlet.com/138350128/connoisseurship-terms-flash-cards/
A French term meaning "okay to print" that designates the final trial proof. Especially if the artist is not printing his/her own edition, the bon a tirer proof tells the printer what the edition should look like. There is only one of these proofs for an edition, and it is usually annotated as B.A.T.
http://people.brandeis.edu/~hsultan/summer09/lalgebra/proofs
Proof — First note that the identity matrix is a diagonal matrix so its determinant is just the product of the diagonal entries. Since all the entries are 1, it follows that det(I n) = 1. Next consider the following computation to complete the proof: 1 = det(I n) = det(AA 1) = det(A)det(A 1) [using the fact that det(AB) = det(A)det(B)] =) det ...
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